# How do you multiply (4x-√3)(4x+√3)?

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An alternative approach is the well-known F.O.I.L. method, which has the drawback of only being able to work with the product of two binomials.

Step 1: Extend the initial terms:

Step 2: Extend the external terms by:

Step 3: Increase the inside terms by one.

Step 4: Increase the final terms by:

Step 5: Add all terms (note that this is a unique instance where the total of the outside and inside terms is zero):

Because the distributive method can handle polynomials of any size, that's why I like it.

Step 1: Divide the second factor among the first factor's terms:

Note that the number of terms in either factor can be used in the aforementioned step, and it makes no difference which factor you distribute.

Please note that the terms we obtained using the F.O.I.L. method are the same as ours.

Step 3: Merge similar terms together:

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To multiply (4x-√3)(4x+√3), you can use the distributive property and the difference of squares formula. First, multiply the terms together:

(4x)(4x) = 16x^2 (4x)(√3) = 4x√3 (-√3)(4x) = -4x√3 (-√3)(√3) = -3

Combine like terms:

16x^2 - 3

So, the result of multiplying (4x-√3)(4x+√3) is 16x^2 - 3.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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