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How do you multiply #(4x-2)(4x+2)#?

Answer 1

Hazel Anglin

Multiply each factor with each factor.

#(4x-2)(4x+2)=4x*4x+4x*2-2*4x-2*2=# #=4^2x^2+(8-8)x-4=16x^2-4#

You can remember this formula: #(a+b)(a-b)=a^2-b^2#

#(a-b)(a+b)=a*a+a*b-b*a-b*b=# #=a^2+(ab-ba)-b^2=a^2-b^2#

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Answer 2

Eli Assouline

To multiply (4x-2)(4x+2), you can use the distributive property or the FOIL method.

First, multiply the terms in each pair of parentheses:

(4x * 4x) + (4x * 2) + (-2 * 4x) + (-2 * 2)

Next, simplify each term:

16x^2 + 8x - 8x - 4

Combine like terms:

16x^2 - 4

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.