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How do you multiply #(4u+7v)^2#?

Answer 1

Avery Alexander

#(4u+7v)^2=16u^2+56uv+49v^2#

#(4u+7v)^2#

= #(4u+7v)(4u+7v)#

= #4u(4u+7v)+7v(4u+7v)#

= #4u×4u+4u×7v+7v×4u+7v×7v#

= #16u^2+28uv+28uv+49v^2#

= #16u^2+56uv+49v^2#

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Answer 2

Avery Alexander

To multiply (4u+7v)^2, you use the formula (a + b)^2 = a^2 + 2ab + b^2. So, (4u+7v)^2 = (4u)^2 + 2 * (4u) * (7v) + (7v)^2. Simplify each term: (4u)^2 = 16u^2, 2 * (4u) * (7v) = 56uv, and (7v)^2 = 49v^2. Combine the terms: 16u^2 + 56uv + 49v^2. So, (4u+7v)^2 = 16u^2 + 56uv + 49v^2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.