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How do you multiply #(3y + 5) ( 6y - 4w - 6)#?

Answer 1

See the entire solution process below:

You multiply each term in the left parenthesis by each term in the right parenthesis to get the product of these two terms.

#(color(red)(3y) + color(red)(5))(color(blue)(6y) - color(blue)(4w) - color(blue)(6))# becomes:

#(color(red)(3y) xx color(blue)(6y)) - (color(red)(3y) xx color(blue)(4w)) - (color(red)(3y) xx color(blue)(6)) + (color(red)(5) xx color(blue)(6y)) - (color(red)(5) xx color(blue)(4w)) - (color(red)(5) xx color(blue)(6))#

#18y^2 - 12yw - 18y + 30y - 20w - 30#

Now, we can mix similar terms:

#18y^2 - 12yw + (-18 + 30)y - 20w - 30#

#18y^2 - 12yw + 12y - 20w - 30#

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Answer 2

Isaiah Anthony

To multiply ( (3y + 5) (6y - 4w - 6) ), you can use the distributive property or the FOIL method.

Using the distributive property:

[ (3y + 5)(6y) = 18y^2 ] [ (3y + 5)(-4w) = -12yw ] [ (3y + 5)(-6) = -18y - 30 ]

So, when you add these terms together, you get:

[ 18y^2 - 12yw - 18y - 30 ]

This is the simplified expression resulting from multiplying ( (3y + 5) (6y - 4w - 6) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.