How do you multiply #(3x – 7)(5x + 6)#?

Answer 1

Multiplying this out gives us #15x^2-17x-42#

So let start by rewriting this thing out again.

#(3x-7)(5x+6)#

So we need to use the FOIL method to see what this will give us.

#15x^2+18x-35x-42#

So once you are finish using the FOIL method, combine the like terms. The final answer to this is:

#15x^2-17x-42#
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Answer 2

#15x^2 - 17x - 42#

To multiply the two binomials #(3x-7)(5x+6)#

We use the mnemonic FOIL

F - First terms #(3x)(5x)=15x^2# O - Outer terms #(3x)(6) = 18x# I - Inner terms #(-7)(5x) = -35x# L - Last terms #(-7)(6) = -42#

Now combine the terms

#15x^2 + 18x - 35x - 42#

Add like terms

#15x^2 - 17x - 42#
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Answer 3

To multiply ((3x - 7)(5x + 6)), you can use the distributive property and multiply each term in the first expression by each term in the second expression. Then, combine like terms to simplify the result. The result is (15x^2 + 18x - 35x - 42), which simplifies to (15x^2 - 17x - 42).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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