How do you multiply #(3x + 4) ( 2x + 5y )#?

Answer 1

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(3x) + color(red)(4))(color(blue)(2x) + color(blue)(5y))# becomes:
#(color(red)(3x) xx color(blue)(2x)) + (color(red)(3x) xx color(blue)(5y)) + (color(red)(4) xx color(blue)(2x)) + (color(red)(4) xx color(blue)(5y))#
#6x^2 + 15xy + 8x + 20y#

Or

#6x^2 + 8x + 15xy + 20y#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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