How do you multiply #(-3x^2+4x+5)(-2x-8)#?

Answer 1

See a solution process below:

You multiply each term in the left parenthesis by each term in the right parenthesis to get the product of these two terms.

#(-color(red)(3x^2) + color(red)(4x) + color(red)(5))(-color(blue)(2x) - color(blue)(8))# becomes:

#(color(red)(-3x^2) xx color(blue)(-2x)) + (color(red)(-3x^2) xx color(blue)(-8)) - (color(red)(4x) xx color(blue)(2x)) - (color(red)(4x) xx color(blue)(8)) - (color(red)(5) xx color(blue)(2x)) - (color(red)(5) xx color(blue)(8))#

#6x^3 + 24x^2 - 8x^2 -32x - 10x - 40#

Now, we can mix similar terms:

#6x^3 + (24 - 8)x^2 + (-32 - 10)x - 40#

#6x^3 + 16x^2 + (-42)x - 40#

#6x^3 + 16x^2 - 42x - 40#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.