How do you multiply #(3m^2-12m)div(m^2-4m)/(m^2-6m+8)#?

Question

Avery Alexander · Accepted Answer

#3m^2-18m+24#

Let's factorise everything we've got:

#(3m^2-12m)/1 div (m^2-4m)/(m^2-6m+8)#

When we are dividing fractions, we can multiply by the reciprocal of the second fraction, so our expression really is

#(3m^2-12m)/1 xx (m^2-6m+8)/(m^2-4m)#

Let's factorise everything we can:

#(3m(m-4))/1 xx ((m-2)(m-4))/(m(m-4))#

Now, let's see what cancels out, meaning what has the same factor in the numerator as the denominator

#(3cancel(m)cancel((m-4)))/1 xx ((m-2)(m-4))/(cancel(m)cancel((m-4)))#

Now let's multiply the fractions. Remember, it's straight across!

#(3 xx (m-2)(m-4))/1#

#3 xx (m^2-6m+8)#

#3m^2-18m+24#

Eva Adamson · Answer

undefined To multiply the expression (3m^2-12m) divided by (m^2-4m) by (m^2-6m+8), you can follow these steps:

1. Factorize the expressions:
   (3m^2-12m) divided by (m^2-4m) can be factored as 3m(m-4) divided by m(m-4).
   (m^2-6m+8) can be factored as (m-4)(m-2).

2. Cancel out the common factors:
   Cancel out the common factor (m-4) in the numerator and denominator.

3. Simplify the expression:
   After canceling out the common factor, the expression becomes:
   3m divided by (m-2).

Therefore, the simplified expression is 3m divided by (m-2).

Jameson Allen · Answer

undefined To multiply the expression (3m^2 - 12m) / (m^2 - 4m) by 1 / (m^2 - 6m + 8), you first need to factorize the denominators and then cancel out any common factors. Factoring the denominators:

m^2 - 4m = m(m - 4)
m^2 - 6m + 8 = (m - 4)(m - 2)

Now, rewrite the expression:

(3m^2 - 12m) / (m^2 - 4m) * 1 / (m^2 - 6m + 8)

= (3m^2 - 12m) / (m(m - 4)) * 1 / ((m - 4)(m - 2))

Now, cancel out the common factors:

= (3m) / (m - 2)