How do you multiply #(3(x-6))/5=(3(x+2))/6#?

Answer 1
  1. Multiplying the terms within brackets:
#(3x- 18)/5# #=# #(3x + 6)/6#
  1. Cross multiplication:
#(3x- 18) xx 6# #=# #(3x + 6) xx 5#
#18x- 108 = 15x + 30# #3x = 138#
# x = 46#
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Answer 2

To solve the equation (3(x-6))/5=(3(x+2))/6, we can start by cross-multiplying. This means multiplying the numerator of the left side by the denominator of the right side, and vice versa.

Cross-multiplying gives us: 6 * (3(x-6)) = 5 * (3(x+2))

Simplifying both sides of the equation, we have: 18(x-6) = 15(x+2)

Expanding the brackets, we get: 18x - 108 = 15x + 30

Next, we can combine like terms by subtracting 15x from both sides: 18x - 15x - 108 = 15x - 15x + 30

Simplifying further, we have: 3x - 108 = 30

To isolate the variable, we can add 108 to both sides: 3x - 108 + 108 = 30 + 108

Simplifying, we get: 3x = 138

Finally, we can solve for x by dividing both sides by 3: 3x/3 = 138/3

The solution is: x = 46

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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