How do you multiply #(3(x-6))/5=(3(x+2))/6#?
- Multiplying the terms within brackets:
- Cross multiplication:
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To solve the equation (3(x-6))/5=(3(x+2))/6, we can start by cross-multiplying. This means multiplying the numerator of the left side by the denominator of the right side, and vice versa.
Cross-multiplying gives us: 6 * (3(x-6)) = 5 * (3(x+2))
Simplifying both sides of the equation, we have: 18(x-6) = 15(x+2)
Expanding the brackets, we get: 18x - 108 = 15x + 30
Next, we can combine like terms by subtracting 15x from both sides: 18x - 15x - 108 = 15x - 15x + 30
Simplifying further, we have: 3x - 108 = 30
To isolate the variable, we can add 108 to both sides: 3x - 108 + 108 = 30 + 108
Simplifying, we get: 3x = 138
Finally, we can solve for x by dividing both sides by 3: 3x/3 = 138/3
The solution is: x = 46
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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