How do you multiply #-3(2x)^4(4x^5y)^2#?
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To multiply (-3(2x)^4(4x^5y)^2), you first apply the power rule for exponents, which states that ( (a^m)^n = a^{mn} ). Then you multiply the coefficients and combine the variables using the laws of exponents.
[ \begin{align*} -3(2x)^4(4x^5y)^2 &= -3(2^4x^4)(4^2x^{10}y^2) \ &= -3(16x^4)(16x^{10}y^2) \ &= -3(16 \times 16)(x^{4+10})(y^2) \ &= -3(256)(x^{14})(y^2) \ &= -768x^{14}y^2 \end{align*} ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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