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How do you multiply #(2x-3)(x^4-2x^2+3)#?

Answer 1

Nathan Axel

#2x^5-3x^4-4x^3+6x^2+6x-9#

Multiply each term in the second bracket by #2x# and then multiply each term by -3.

#(2x-3)(x^4-2x^2+3)#

#2x^5-4x^3+6x-3x^4+6x^2-9#

#2x^5-3x^4-4x^3+6x^2+6x-9#

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Answer 2

Jace Anderson

To multiply (2x-3)(x^4-2x^2+3), you can use the distributive property or the FOIL method:

(2x-3)(x^4-2x^2+3) = 2x * (x^4-2x^2+3) - 3 * (x^4-2x^2+3)

Now, distribute each term:

= 2x * x^4 - 2x * 2x^2 + 2x * 3 - 3 * x^4 + 3 * 2x^2 - 3 * 3

Simplify each term:

= 2x^5 - 4x^3 + 6x - 3x^4 + 6x^2 - 9

Combine like terms:

= 2x^5 - 3x^4 - 4x^3 + 6x^2 + 6x - 9

So, (2x-3)(x^4-2x^2+3) = 2x^5 - 3x^4 - 4x^3 + 6x^2 + 6x - 9.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.