How do you multiply #(2x-3)/(25x^2-1)*(15x^2-7x-2)/(6x^2-13x+6)#?

Answer 1

Eli Assouline

Multiplying functions is easy: you just mutiply numerator by numerator and denominator by denominator.

This way: #(30x^3-14x^2-4x-45x^2+21x+6)/(150x^4-325x^3+150x^2-6x^2+13x-6)#

Just sum the elements with the same exponent:

#(30x^3-59x^2+17x+6)/(150x^4-325x^3+144x^2+13x-6)#

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Answer 2

Ethan Adkins

To multiply the given expressions, you can follow these steps:

Factorize each polynomial expression: (2x-3) = (x-1)(2x+3) (25x^2-1) = (5x-1)(5x+1) (15x^2-7x-2) = (3x+2)(5x-1) (6x^2-13x+6) = (2x-3)(3x-2)
Cancel out any common factors between the numerators and denominators.
Multiply the remaining factors together: [(x-1)(2x+3)(3x+2)] / [(5x+1)(2x-3)(3x-2)]

This is the simplified form of the multiplication of the given expressions.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.