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How do you multiply # (2x+12)/(3x-9) * (2x-6)/(3x+8)#?

Answer 1

Nathan Axel

#(4(x+6)(x-3))/(3(x-3)(3x+8))# #=(4(x+6))/(3(3x+8))#

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Answer 2

Ethan Adkins

To multiply the given expressions, you can follow these steps:

Multiply the numerators together: (2x + 12) * (2x - 6)
Multiply the denominators together: (3x - 9) * (3x + 8)
Simplify each expression separately.
Write the simplified expressions as the numerator and denominator of the final fraction.

Let's go through the steps:

Expanding the numerator: (2x + 12) * (2x - 6) = 4x^2 - 12x + 24x - 72 = 4x^2 + 12x - 72
Expanding the denominator: (3x - 9) * (3x + 8) = 9x^2 + 24x - 27x - 72 = 9x^2 - 3x - 72
Simplifying the numerator and denominator expressions: Numerator: 4x^2 + 12x - 72 Denominator: 9x^2 - 3x - 72

Therefore, the final expression is: (4x^2 + 12x - 72) / (9x^2 - 3x - 72)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.