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How do you multiply #(2a - 5) ( 3a + 1) #?

Answer 1

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(2a) - color(red)(5))(color(blue)(3a) + color(blue)(1))# becomes:

#(color(red)(2a) xx color(blue)(3a)) + (color(red)(2a) xx color(blue)(1)) - (color(red)(5) xx color(blue)(3a)) - (color(red)(5) xx color(blue)(1))#

#6a^2 + 2a - 15a - 5#

We can now combine like terms:

#6a^2 + (2 - 15)a - 5#

#6a^2 + (-13)a - 5#

#6a^2 - 13a - 5#

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Answer 2

Jace Anderson

To multiply ((2a - 5)(3a + 1)), you can use the distributive property or the FOIL method:

Using the distributive property: [ (2a - 5)(3a + 1) = 2a \cdot 3a + 2a \cdot 1 - 5 \cdot 3a - 5 \cdot 1 ]

Simplify each term and combine like terms to get the final result.

Using the FOIL method: [ (2a - 5)(3a + 1) = (2a \cdot 3a) + (2a \cdot 1) + (-5 \cdot 3a) + (-5 \cdot 1) ]

Multiply the terms in each set of parentheses, then combine like terms to simplify and get the final result.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.