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How do you multiply #(2)/(x^2+1)*(3)/(2x)#?

Answer 1

You multiply numerator with numerator and denominator with denominator as: #(2*3)/(2x(x^2+1))=(cancel(2)*3)/(cancel(2)x(x^2+1))=3/(x(x^2+1))#

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Answer 2

Kennedy Adams

To multiply (2)/(x^2+1) and (3)/(2x), you can follow these steps:

Multiply the numerators together: 2 * 3 = 6.
Multiply the denominators together: (x^2+1) * (2x) = 2x(x^2+1) = 2x^3 + 2x.
Combine the results from steps 1 and 2: 6/(2x^3 + 2x).

Therefore, the product of (2)/(x^2+1) and (3)/(2x) is 6/(2x^3 + 2x).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.