How do you multiply # 1 / (x(x - 2))+ x /(x - 2) = 10/ x#?
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To solve the equation 1 / (x(x - 2)) + x / (x - 2) = 10 / x, we can start by finding a common denominator for the fractions on the left side of the equation. The common denominator is x(x - 2).
Multiplying the first fraction by (x - 2) / (x - 2) and the second fraction by x / x, we get:
[(1 * (x - 2)) / (x(x - 2))] + [(x * x) / (x(x - 2))] = 10 / x
Simplifying the fractions, we have:
[(x - 2) / (x^2 - 2x)] + (x^2 / (x^2 - 2x)) = 10 / x
Combining the fractions, we get:
[(x - 2) + x^2] / (x^2 - 2x) = 10 / x
Expanding the numerator, we have:
(x - 2 + x^2) / (x^2 - 2x) = 10 / x
Rearranging the equation, we get:
(x^2 + x - 2) / (x^2 - 2x) = 10 / x
Cross-multiplying, we have:
x(x^2 + x - 2) = 10(x^2 - 2x)
Expanding both sides, we get:
x^3 + x^2 - 2x = 10x^2 - 20x
Rearranging the equation, we have:
x^3 + x^2 - 10x^2 + 20x - 2x = 0
Combining like terms, we get:
x^3 - 9x^2 + 18x - 2x = 0
Simplifying further, we have:
x^3 - 9x^2 + 16x = 0
Factoring out an x, we get:
x(x^2 - 9x + 16) = 0
Factoring the quadratic expression, we have:
x(x - 1)(x - 16) = 0
Therefore, the solutions to the equation are x = 0, x = 1, and x = 16.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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