How do you multiply #1/(2x) + 3/(x+7) = -1/x#?

Answer 1
# (1/(2x)) + (3 /(x+7)) = -(1/x)# # (1/(2x)) + (1/x) = -(3 /(x+7))#
# (1/(2x)) + ((1 xx 2)/(x xx 2)) = -(3 /(x+7))#
L.C.M of the L.H.S is #2x#
# (1/(2x)) + ((2)/(2x)) = -(3 /(x+7))#
# 3/(2x) = -(3 /(x+7))#
# 3/(2x) = (-3) /(x + 7)#
on cross multiplying: # 3 xx (x + 7) = (-3) xx (2x)#
# 3x + 21 = -6x#
# 9x = -21#
# x = -7/3#
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Answer 2

To solve the equation 1/(2x) + 3/(x+7) = -1/x, we need to find a common denominator and combine the fractions. The common denominator is 2x(x+7). Multiplying each term by the common denominator, we get (x+7) + 6x = -2(x+7). Simplifying, we have x + 7 + 6x = -2x - 14. Combining like terms, we get 7x + 7 = -2x - 14. Moving all the terms to one side, we have 7x + 2x = -14 - 7. Simplifying further, we get 9x = -21. Dividing both sides by 9, we find x = -21/9, which simplifies to x = -7/3. Therefore, the solution to the equation is x = -7/3.

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Answer 3

To multiply the equation ( \frac{1}{2x} + \frac{3}{x+7} = -\frac{1}{x} ) by ( 2x(x + 7) ), you would multiply each term in the equation by ( 2x(x + 7) ). This step is taken to clear the denominators and simplify the equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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