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How do you multiply #(0.2y+1.7)^2#?

Answer 1

Genesis Allen

This is my handwriting only #(0.2y+1.7)^2#

#=(0.2y+1.7)(0.2y+1.7)#

#= 0.04y^2 +0.34y+0.34y + 2.89#

#=0.04y^2 +0.68y +2.89#

Or as shown above, using the 'short cut' identity:

#(a+b)^2 =a^2 +2ab +b^2#

#(0.2y+1.7)^2#

#=0.04y^2 +0.68y +2.89#

Terms are usually arranged in descending order of the powers.

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Answer 2

Eva Adamson

To multiply (0.2y + 1.7)^2, you would expand it using the formula for squaring a binomial, which is (a + b)^2 = a^2 + 2ab + b^2. Applying this formula, you would square each term in the binomial, then multiply the terms together and combine like terms to simplify the expression. The result would be 0.04y^2 + 0.68y + 2.89.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.