How do you long divide # x^3  7x  6 div x+1 #?
by Ruffini rule
Ruffini scheme:
first row I get coefficients,
second row on the left the known term with changed sign (1) and
I get results of sums in columns and products by 1
third row: I get result's coefficients
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To long divide ( x^3  7x  6 ) by ( x+1 ), follow these steps:

Divide the first term of the dividend (( x^3 )) by the first term of the divisor (( x )), which gives ( x^2 ). Write this as the first term of the quotient.

Multiply the entire divisor (( x+1 )) by ( x^2 ) and write the result below the dividend.

Subtract the result obtained in step 2 from the dividend (( x^3  x^3  x^2 )). This leaves ( x^2  7x  6 ).

Bring down the next term from the dividend, which is ( 7x ).

Repeat steps 13 using the result obtained from step 4 as the new dividend (( x^2  7x )).

Continue this process until all terms in the dividend have been used.

The final result will be the quotient (( x^2  8x + 1 )) and the remainder (0).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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