How do you integrate #(x+3) / sqrt(x) dx#?
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To integrate ( \frac{x+3}{\sqrt{x}} ) with respect to ( x ), you can use substitution. Let ( u = \sqrt{x} ), then ( x = u^2 ) and ( du = \frac{1}{2\sqrt{x}}dx ). Substituting, the integral becomes:
[ \int \frac{x+3}{\sqrt{x}} , dx = \int \frac{u^2 + 3}{u} \cdot 2u , du ]
[ = \int (2u + \frac{3}{u}) , du ]
[ = \int 2u , du + \int \frac{3}{u} , du ]
[ = u^2 + 3\ln|u| + C ]
[ = x + 3\sqrt{x} + C ]
Where ( C ) is the constant of integration.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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