# How do you integrate #(x ^ { 2} + 8) ^ { 4} 2x d x#?

one way is by inspection

we note that the outside of the bracket is a multiple of the bracket differentiated

comparing this with the integral we just adjust the multiple.

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To integrateTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u =To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = xTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2xTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{duTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x)To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ).To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2xTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). NowTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now,To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ).To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). NowTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( uTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now,To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u =To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substituteTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = xTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( uTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u =To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 +To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 +To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 )To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) andTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dxTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 )To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx =To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) andTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = duTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dxTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x)To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \fracTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) )To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{duTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) intoTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into theTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integralTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2xTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral.To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x}To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. TheTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integralTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} )To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomesTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into theTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral.To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int uTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. TheTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integralTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , duTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \intTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int uTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ).To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). IntegrateTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 ,To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , duTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 )To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

IntTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) withTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

IntegrTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respectTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

IntegratingTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect toTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( uTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( uTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) toTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 )To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to getTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respectTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect toTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \fracTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( uTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u )To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) givesTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5}To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} uTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \fracTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 +To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{uTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + CTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ),To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5}To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( CTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + CTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C )To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) isTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), whereTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constantTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant ofTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integrationTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C )To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. SubstituteTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) isTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute backTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is theTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constantTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( uTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integrationTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = xTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration.To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. SubstituteTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u =To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = xTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 )To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) toTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to getTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 +To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get theTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the finalTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final resultTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result:To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) toTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to getTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \fracTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the finalTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final resultTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result:To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5}To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \fracTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (xTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{(To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (x^To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{(xTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (x^2To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{(x^To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (x^2 +To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{(x^2To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (x^2 + To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{(x^2 +To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (x^2 + 8To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{(x^2 + To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (x^2 + 8)^To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{(x^2 + 8)^To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (x^2 + 8)^5To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{(x^2 + 8)^5To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (x^2 + 8)^5 +To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{(x^2 + 8)^5}{To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (x^2 + 8)^5 + CTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{(x^2 + 8)^5}{5To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (x^2 + 8)^5 + C \To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{(x^2 + 8)^5}{5}To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (x^2 + 8)^5 + C ).To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{(x^2 + 8)^5}{5} +To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (x^2 + 8)^5 + C ).To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{(x^2 + 8)^5}{5} + CTo integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = du/(2x) ). Now, substitute ( u = x^2 + 8 ) and ( dx = du/(2x) ) into the integral. The integral becomes ( \int u^4 , du ). Integrate ( u^4 ) with respect to ( u ) to get ( \frac{1}{5} u^5 + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{1}{5} (x^2 + 8)^5 + C ).To integrate ( (x^2 + 8)^4 \cdot 2x , dx ), you can use the substitution method. Let ( u = x^2 + 8 ), then ( du/dx = 2x ), which implies ( dx = \frac{du}{2x} ). Now, substitute ( u = x^2 + 8 ) and ( dx = \frac{du}{2x} ) into the integral. The integral becomes ( \int u^4 , du ).

Integrating ( u^4 ) with respect to ( u ) gives ( \frac{u^5}{5} + C ), where ( C ) is the constant of integration. Substitute back ( u = x^2 + 8 ) to get the final result: ( \frac{(x^2 + 8)^5}{5} + C ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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