# How do you integrate #intsqrt(9-x^2)dx#?

Try this:

By signing up, you agree to our Terms of Service and Privacy Policy

To integrate ∫√(9 - x^2) dx, you can use the substitution method. Let x = 3sin(u), then dx = 3cos(u) du. Substitute these into the integral, simplify, and integrate. The result is (9/2)arcsin(x/3) + (3/2)x√(9 - x^2) + C, where C is the constant of integration.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you integrate #3/((x-2)(x+1))# using partial fractions?
- How do you integrate #int x^3e^(x^2)# by integration by parts method?
- What is #f(x) = int e^xcosx-tan^3x+sinx dx# if #f(pi/6) = 1 #?
- How do I find the integral #intcos(x)ln(sin(x))dx# ?
- How do you integrate #(3x) / (x^2 * (x^2+1) )# using partial fractions?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7