# How do you integrate #int y^2sqrtydy#?

#int \ y^2sqrt(y) \ dy = 2/7y^3sqrt(y) + c#

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To integrate (\int y^2 \sqrt{y} , dy), use the substitution method. Let (u = \sqrt{y}), then (y = u^2). Rewrite the integral in terms of (u), and also express (dy) in terms of (du). After substitution, integrate with respect to (u). Finally, revert back to the original variable (y).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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