How do you integrate #int (x^(3/2)+2x+1)dx#?
where c is the integration constant.
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To integrate ( \int (x^{3/2} + 2x + 1) , dx ), you can use the power rule for integration. First, add 1 to the exponent of each term and then divide by the new exponent. So:
[ \begin{align*} \int (x^{3/2} + 2x + 1) , dx &= \frac{2}{5}x^{5/2} + x^2 + x + C \end{align*} ]
Where ( C ) is the constant of integration.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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