How do you integrate #int sec(1-x)tan(1-x)dx#?
I found:
Have a look:
By signing up, you agree to our Terms of Service and Privacy Policy
To integrate ( \int \sec(1-x) \tan(1-x) , dx ), you can use the substitution method. Let ( u = 1 - x ). Then, ( du = -dx ).
The integral becomes ( -\int \sec(u) \tan(u) , du ).
This integral can be simplified using the substitution ( v = \sec(u) ). Then, ( dv = \sec(u) \tan(u) , du ).
The integral now becomes ( -\int dv ).
Integrating ( dv ) gives ( -v + C ), where ( C ) is the constant of integration.
Substituting back for ( v ) and ( u ), we have ( -\sec(1-x) + C ).
So, ( \int \sec(1-x) \tan(1-x) , dx = -\sec(1-x) + C ).
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7