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How do you integrate #int (2t^2-1)^2dt#?

Answer 1

Scarlett Allison

#(4t^5)/5 -(4t^3)/3 +t +C#

Expand #(2t^2-1)^2 = 4t^4 - 4t^2 +1#

Integrate now, term by term.

#int (4t^4-4t^2+1)dt = (4t^5)/5 -(4t^3)/3 +t +C#

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Answer 2

William Abdalla

To integrate ( \int (2t^2 - 1)^2 , dt ), you can expand the expression ((2t^2 - 1)^2), then integrate each term individually. After expanding and integrating each term, you can combine them to find the final result.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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