# How do you integrate #int (1-x^2)/((x+1)(x-6)(x+2)) # using partial fractions?

=

I just broke down the integrand.

Following denominator expansion,

Hence,

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THe answer is

Divide the breakdown into partial fractions.

Compare the numerators; the denominators are the same.

Consequently,

So,

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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