How do you integrate #cos2x#?

Answer 1
You can set #2x=t#
so that #x=t/2# and #dx=1/2dt#

Your integral changes to:

#intcos(t)/2dt=sin(t)/2+c#
and going back to #x#
#=sin(2x)/2+c#
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Answer 2

To integrate cos^2(x), you can use the trigonometric identity cos^2(x) = (1 + cos(2x))/2. Then, you integrate using this identity to simplify the expression and proceed with the integration. So, the integral of cos^2(x) with respect to x becomes ∫(1 + cos(2x))/2 dx. Split the integral into two separate integrals: ∫(1/2) dx + ∫(cos(2x)/2) dx. Integrate each term separately: (1/2)x + (1/4)sin(2x) + C, where C is the constant of integration. So, the final result is ((1/2)x + (1/4)sin(2x)) + C.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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