How do you integrate by substitution #int x(4x^2+3)^3 dx#?
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To integrate by substitution, we set ( u = 4x^2 + 3 ), then differentiate to find ( du = 8x , dx ). Rearrange to solve for ( dx ). The integral becomes ( \frac{1}{8} \int u^3 , du ). Integrate ( u^3 ) to get ( \frac{1}{32}u^4 ), then substitute back for ( u ) to get ( \frac{1}{32}(4x^2 + 3)^4 ). Finally, multiply by ( \frac{1}{8} ) to get the final answer ( \frac{1}{256}(4x^2 + 3)^4 + C ), where ( C ) is the constant of integration.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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