How do you integrate #9sin(ln x) dx#

Answer 1

I would use: Substitution, Integration by Parts (twice) and a little trick:

hope it helps.

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Answer 2

To integrate ( 9\sin(\ln x) , dx ), you use the substitution method. Let ( u = \ln x ), then ( du = \frac{1}{x} , dx ). Substituting ( u ) and ( du ), the integral becomes ( 9\sin(u) , du ). Integrating ( \sin(u) ) with respect to ( u ) yields ( -9\cos(u) + C ), where ( C ) is the constant of integration. Finally, substitute back ( u = \ln x ) to get the result ( -9\cos(\ln x) + C ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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