How do you integrate # 3^x#?

Answer 1

#= 1/(ln 3) 3^x + C#

We can work the derivative first

#y = 3^x#
#ln y = x ln 3#
#1/y y' = ln 3 #
#y' = ln 3 \ 3^x#
#implies int 3^x \ dx#
#= int d/dx(1/(ln 3) 3^x )\ dx#
#= 1/(ln 3) 3^x + C#
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Answer 2

To integrate 3^x, you can use the formula for the integral of a constant raised to the power of x. The integral of a^x dx is (1/ln(a)) * a^x + C, where C is the constant of integration.

Therefore, integrating 3^x, you get:

∫3^x dx = (1/ln(3)) * 3^x + C

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Answer 3

To integrate 3^x, use the formula for the integral of a exponential function:

∫3^x dx = (1/ln(3)) * 3^x + C

Where C is the constant of integration.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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