# How do you integrate #2 ln (x-5)#?

The given

So that

God bless....I hope the explanation is useful.

By signing up, you agree to our Terms of Service and Privacy Policy

To integrate 2 ln (x - 5), you can use integration by parts. Let u = ln(x - 5) and dv = 2 dx. Differentiate u to find du/dx, and integrate dv to find v. Then, apply the integration by parts formula: ∫u dv = uv - ∫v du. Calculate uv and ∫v du, and subtract the latter from the former to obtain the integral.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you use Integration by Substitution to find #inttan(x)*sec^3(x)dx#?
- How do you integrate #int (3x^3+2x^2-7x-6)/(x^2-4) dx# using partial fractions?
- What is the antiderivative of #ln(1-x)/x#?
- How do you evaluate the integral #int dx/(x^3+x)#?
- How do you integrate #int (2x+1)/((x+4)(x-1)(x+7)) # using partial fractions?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7