# How do you integrate #(13x + 2)/( x^3 -1)# using partial fractions?

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To integrate (13x + 2)/(x^3 - 1) using partial fractions, first factor the denominator as (x - 1)(x^2 + x + 1). Then, express the fraction in the form of partial fractions as A/(x - 1) + (Bx + C)/(x^2 + x + 1). Find the values of A, B, and C by comparing coefficients, and then integrate each term separately.

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