# How do you implicitly differentiate #-1=y^2+(x-e^y)/(x)#?

See answer below:

By signing up, you agree to our Terms of Service and Privacy Policy

To implicitly differentiate -1=y^2+(x-e^y)/(x), first, differentiate each term with respect to x, then apply the chain rule when necessary:

d/dx(-1) = 0 d/dx(y^2) = 2y(dy/dx) d/dx((x-e^y)/(x)) = [(x)(1) - (x-e^y)(1/x)] / x^2

So, the implicit differentiation yields:

0 = 2y(dy/dx) + [(x - e^y) - (x-e^y)/x] / x^2

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7