How do you identify the important parts of #y = x^2 – 2x# to graph it?
We can write your function in the general form:
Basically, to graph your function (that is a Quadratic, representing a Parabola) you need to observe:
1) the coefficient
If it is
2) the vertex: this is the highest/lowest point reached by your parabola and the parabola is plotted all around it. The coordinates of this special point are given as:
So vertex
3) y-intercept. You can set 4) x-intercept(s) (when they exist). You set You can now plot your parabola using mainly these points:
and:
So x-intercepts at
By signing up, you agree to our Terms of Service and Privacy Policy
To identify the important parts of the function y = x^2 - 2x in order to graph it, you need to find the vertex, the axis of symmetry, and the intercepts. The vertex is (-b/2a, f(-b/2a)), where a and b are the coefficients of the quadratic equation. The axis of symmetry is x = -b/2a. The y-intercept is found by substituting x = 0 into the equation, and the x-intercepts are found by solving the equation for y = 0. Additionally, you can find the direction of the parabola by examining the coefficient of x^2.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you solve #x^2 = 8x – 12#?
- A blue spruce grows and average of 6 inches per year. A hemlock grows an average of 4 inches per year. If a blue spruce is 4 feet tall and a hemlock is 6 feet tall, when would u expect the trees to be the same height?
- What is the vertex of #y=3(3x-3)^2+3#?
- What is the vertex of the parabola #y=(x+8)^2+1#?
- Where is the vertex of the graph of #y = x^2 + 4x + 5# located?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7