# How do you identify all vertical asymptotes for #f(x)=(3x^2)/(x^2-1)#?

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non-zero for these values then they are vertical asymptotes.

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To identify vertical asymptotes for ( f(x) = \frac{3x^2}{x^2 - 1} ), find the values of ( x ) that make the denominator equal to zero. These values are the vertical asymptotes. So, set the denominator equal to zero and solve for ( x ).

( x^2 - 1 = 0 )

( x^2 = 1 )

( x = \pm 1 )

Therefore, there are vertical asymptotes at ( x = -1 ) and ( x = 1 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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