How do you graph #y+x<=5#?

Answer 1

Since this inequality is linear, we need two points and a line; the area below the line represents our solution space.

graph{5-x [-5.92, 14.08, -1.92, 8.08]} occurs when #x=0->y<=5# and when #y=0->x<=5#.
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Answer 2

To graph the inequality ( y + x \leq 5 ), first, graph the boundary line ( y + x = 5 ).

To do this, rewrite the equation in slope-intercept form: ( y = -x + 5 ).

Then, plot the y-intercept at 5 and use the slope -1 (since the coefficient of x is -1) to find another point.

Draw a dashed line through these points, since the inequality is inclusive (≤) and not strict.

Finally, shade the region below the boundary line to represent all points that satisfy the inequality.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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