How do you graph #y = -½ x + 3# by plotting points?

Answer 1

See the explanation.

#y=-1/2x+3# is the slope intercept form of a linear equation.
Determine two points on the line by substituting values for #x# into the equation and solving for #y#. You only need two points for a straight line.
Table of Points #x=0,# #y=3# #x=6,# #y=0#

Plot the points and draw a straight line through the points.

graph{y=-1/2x+3 [-10, 10, -5, 5]}

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Answer 2

To graph the equation y = -½ x + 3 by plotting points, you can choose values for x and then calculate the corresponding y values using the equation. For example:

When x = 0: y = -½ (0) + 3 y = 3

When x = 2: y = -½ (2) + 3 y = 2

When x = -4: y = -½ (-4) + 3 y = 5

Plot the points (0, 3), (2, 2), and (-4, 5) on the coordinate plane, and draw a line passing through these points to represent the graph of the equation y = -½ x + 3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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