How do you graph #y = -½ x + 3# by plotting points?
See the explanation.
Plot the points and draw a straight line through the points.
graph{y=-1/2x+3 [-10, 10, -5, 5]}
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To graph the equation y = -½ x + 3 by plotting points, you can choose values for x and then calculate the corresponding y values using the equation. For example:
When x = 0: y = -½ (0) + 3 y = 3
When x = 2: y = -½ (2) + 3 y = 2
When x = -4: y = -½ (-4) + 3 y = 5
Plot the points (0, 3), (2, 2), and (-4, 5) on the coordinate plane, and draw a line passing through these points to represent the graph of the equation y = -½ x + 3.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- What is the slope of the line passing through the following points: # (-3, -1) ; (0,2)#?
- How do you find slope and y-intercept of #y=-3#?
- How do you find the slope of the straight line that passes through (–2, –4) and (3, –5)?
- How do you graph 4x=-y+2 by plotting points?

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