Home > Precalculus > Polynomial Inequalities

How do you graph #y < x^2- 5x#?

Answer 1

Madelyn Anderson

We seek a graph of the region #y lt x^2-5x#

First we draw the graph of the parabola #y=x^2-5x# graph{y=x^2-5x [-3, 8, -8, 4]}

Then the sought region is that below the parabola: graph{y-x^2+5x<0 [-3, 8, -8, 4]}

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Lincoln Anderson

To graph (y < x^2 - 5x), follow these steps:

Graph the parabola (y = x^2 - 5x).
Since the inequality is (y < x^2 - 5x), the region below the parabola is shaded.
The parabola opens upward, so you'll shade the region below the curve.
You can use a dashed line to represent the boundary because the inequality is strict ((<)), meaning the points on the curve are not included.
This shading represents all the points where (y) is less than (x^2 - 5x).

That's how you graph (y < x^2 - 5x).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you graph #y &lt; x^2- 5x#?

How do you graph #y < x^2- 5x#?