How do you graph #y= (x-12)^2 -7 #?

Answer 1

Hazel Anglin

Simplify the function y = #x^2 - 24x +137#

Find its vertex

x = #(-b)/(2a) = 24/2 #= 12

Take a few points on both sides of 12

x : y 9 : 2 10 : -3 11 : -6 12 : -7 13 : -6 14 : -3 15 : 2 16 : 9

Polt the points and join them with a smooth line graph{x^2-24x+137 [-20.27, 20.29, -10.14, 10.13]}

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Answer 2

Isaiah Anthony

To graph the equation y = (x - 12)^2 - 7, you can start by plotting the vertex at (12, -7). Then, use the symmetry of the graph to plot additional points symmetrically on either side of the vertex. You can also find the y-intercept by substituting x = 0 into the equation. Finally, connect the points to form the parabola.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.