How do you graph #y \le 4x+3#?

Answer 1

First, sketch the line #y=4x+3# (in a solid line since it is not a strict inequality), which looks like:

Choose any sample point that is NOT on the line. I use #(0,0)# to see if it satisfies the inequality:

#0 le 4(0)+3#.

Since #(0,0)# satisfies the inequality, we shade the side containing #(0,0)#, which looks like:

That is how you graph #y le 4x+3#.


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Answer 2

To graph ( y \leq 4x + 3 ), you would first graph the line ( y = 4x + 3 ) as a solid line. Then, since the inequality includes the "or equal to" sign (( \leq )), you would shade the region below the line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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