How do you graph #y=7/2x-2#?

Question

Nathan Axel · Accepted Answer

See procedure below.

The following procedure will give you the coordinates of 2 data points. As we work them out, put them on your graph paper. Then you can draw a line between them and extend them as far as you like. Plug in 0 for y and find the value of x that satisfies the equation: #y = 7/2x - 2# If #y = 0#, then #0 = 7/2x - 2# Now, solve for x. Add 2 to both sides. Then we have #2 = 7/2*x# Multiply both sides by #2/7#. So #2/7*2 = 2/7*7/2*x# Cancel where possible. #2/7*2 = cancel(2)/cancel(7)*cancel(7)/cancel(2)*x# So we have #x = 4/7# Therefore, you can plot a data point at #(4/7,0)# Repeat, except plug in 0 for x. Starting with: #y = 7/2x - 2# If #x = 0#, then #y = 7/2*0 - 2# That simplifies to #y = - 2# Therefore you can plot a second point at #(0,-2)#. Those are the 2 points that cross the x-y axes. Draw the line. I hope this helps, Steve

Ethan Adkins · Answer

undefined To graph the equation $ y = \frac{7}{2}x - 2 $, follow these steps:

1. Choose a set of values for $ x $. For example, you can choose $ x = -2, -1, 0, 1, 2 $.
2. Substitute each value of $ x $ into the equation to find the corresponding values of $ y $.
3. Plot the points $ (x, y) $ on a coordinate plane.
4. Draw a straight line through the points to represent the graph of the equation.