How do you graph #y+5x=-5#?
see explanation
This is the equation of a line . To graph a line only requires 2 points although a 3rd is useful for alignment of the points.
When the line crosses the x-axis , the y-coord will be zero. Substitute y = 0 into equation to find corresponding x-coord.
y = 0 : 5x = - 5 → x = -1 → (-1,0) is a point on line.
Similarly, when the line crosses the y-axis , x will be zero.
x = 0 : y = -5 → (0,-5) is a 2nd point on the line.
For a 3rd point, choose any value of x , say x = 1
x = 1: y +5 = -5 → y = -10 → (1,-10) is a 3rd point
Now , plot (-1,0),(0,-5) and (1,-10) and draw a straight line through them.
Here is the graph as a check. graph{-5x-5 [-10, 10, -5, 5]}
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To graph the equation ( y + 5x = -5 ), follow these steps:
- Rewrite the equation in slope-intercept form: ( y = -5x - 5 ).
- Identify the y-intercept, which is -5.
- Use the slope (-5) to find another point. For example, if x = 0, then y = -5.
- Plot these two points: (0, -5) and (1, -10).
- Draw a straight line through the points to graph the equation.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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