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How do you graph # y=5x+1#?

Answer 1

see graph below

graph{5x+1 [-0.968, 1.732, 0.412, 1.762]} 2.433, -1.214, 1.219]} you first have to plot your y-intercept which would be #1# and then you use the formula for slope #(rise)/(run)# which would be up #5# and over #1#. #1# because the #5# is alone and so you imagine a #1# under it

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Answer 2

Jace Anderson

To graph the equation (y = 5x + 1), you can use the slope-intercept form of a linear equation, which is (y = mx + b), where (m) represents the slope and (b) represents the y-intercept.

For the equation (y = 5x + 1), the slope ((m)) is 5 and the y-intercept ((b)) is 1.

To graph it:

Start by plotting the y-intercept, which is the point (0, 1).
Use the slope to find another point on the line. Since the slope is 5, you can move 5 units up and 1 unit to the right from the y-intercept. This gives you the point (1, 6).
Connect the two points with a straight line to graph the equation.

This line represents the graph of the equation (y = 5x + 1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.