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How do you graph #y=5x-1#?

Answer 1

Nathan Axel

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (5 * 0) - 1#

#y = 0 - 1#

#y = -1# or #(0, -1)#

Second Point: For #x = 1#

#y = (5 * 1) - 1#

#y = 5 - 1#

#y = 4# or #(1, 4)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+1)^2-0.035)((x-1)^2+(y-4)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - 5x + 1)(x^2+(y+1)^2-0.035)((x-1)^2+(y-4)^2-0.035)=0 [-10, 10, -5, 5]}

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Answer 2

Julia Adams

To graph the equation ( y = 5x - 1 ), you need to plot points on a coordinate plane. Start by choosing values for ( x ), then use the equation to find the corresponding ( y ) values. Plot these points and connect them with a straight line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.