How do you graph #y=5sqrtx#?

Answer 1

You asked "how do you graph". This has been provided.

Consider this example:

#2^2=4 #

The thing is; #(-2)xx(-2) = +4" so "sqrt(4)# could be -2

Also #(+2)xx(+2)=+4" so "sqrt(4)# could be +2 as well

Thus we have #sqrt(4)=+-2#
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So for your question:
#y=5sqrt(x)# in fact is #y=+-5sqrt(x)#

#color(magenta)("The trap")#

Suppose #x# is negative. Then the square root takes you into the realm of complex numbers.

#color(red)("Assumption: "x" is not negative.")#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Build a table of values calculating what #y# is for the selected values of #x#. Remembering that #x# is not negative.

Note that for each value of #x# there will be corresponding values of #+-y#

Plot the points and draw a line through the points as best as you can.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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