How do you graph #y-5=3(x-1)#?

Your graph: graph{(3*x)+2 [-5, 5, -5, 5]}

To graph the equation (y - 5 = 3(x - 1)), you can use the slope-intercept form (y = mx + b), where (m) is the slope and (b) is the y-intercept.

First, you need to rearrange the given equation into slope-intercept form:

[y - 5 = 3(x - 1)]

[y = 3(x - 1) + 5]

Now, distribute 3:

[y = 3x - 3 + 5]

[y = 3x + 2]

The equation is now in slope-intercept form, with slope (m = 3) and y-intercept (b = 2).

To graph the line, start by plotting the y-intercept at (y = 2). Then, use the slope to find another point on the line. Since the slope is (m = 3), it means that for every one unit increase in (x), (y) increases by three units.

So, starting from the y-intercept at (x = 0, y = 2), move one unit to the right and three units up to get the next point. Continue this pattern to draw the line.