How do you graph # y=4x+8#?

Question

How do you graph  # y=4x+8#?

Avery Alexander · Accepted Answer

Make a point at #(0,8)# then move up 4 on the y and over 1 on the #x# and make another point at #( 1,12)# draw a line to connect the points.

The equation is in the # y = mx +b# y intercept form. where #m =# the slope ( think mountain slope ski resort) #b =# the #y# intercept ( think beginning pony) The equation # y= 4x + 8# #m = 4/1color(white)(000)# The change in #y# is 4 and the change in #x# is 1 #b= 8color(white)(000)# The line crosses the #y# axis at #( 0,8)# Start at the y intercept 8 make a point at #( 0,8)# Then use the slope Go up 4 on the #y# axis # 8+ 4 = 12# The #y# value of the second point is 12 Go over 1 on the #x# axis # 0 + 1 = 1# the #x# value of the second point is 1. make a second point at #( 1,12)# Connect the dots. graph{4x+8 [-18.27, 13.77, -3.68, 12.35]}

Genesis Allen · Answer

undefined To graph the equation y = 4x + 8, you can start by plotting the y-intercept, which is 8. Then, you can use the slope, which is 4, to plot additional points. For example, if you move one unit to the right (increase x by 1), you would move up 4 units (multiply the change in x by the slope, which is 4) to find the next point. Connect the points with a straight line to complete the graph.