How do you graph #y = 4x + 3#?

Answer 1

The #y#-intercept is #0,3#, and the slope is #4#.

We know that the #y#-intercept is #3#, and that means that we start there. From there, we rise 4 units and go over (run) 1 unit.
I got this information from #y=mx+b#, where #x=#slope, and #b=# the #y#-intercept.
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Answer 2

To graph the equation y = 4x + 3, you can use the slope-intercept form, which is y = mx + b. In this equation, m represents the slope of the line, and b represents the y-intercept.

For y = 4x + 3, the slope is 4, and the y-intercept is 3. To graph this equation, start by plotting the y-intercept at the point (0, 3). Then, use the slope to find additional points on the line.

Since the slope is 4, this means that for every 1 unit increase in x, y increases by 4 units. So, from the y-intercept (0, 3), move 1 unit to the right (increasing x by 1) and 4 units up (increasing y by 4) to plot another point.

Repeat this process to plot more points, and then draw a straight line through the points to represent the graph of y = 4x + 3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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