How do you graph #y= 4x^2 -24x +1#?

Answer 1

Refer explanation section

y = graph{ 4x^2 - 24x + 1 [-83.3, 83.3, -41.64, 41.7]}

Find the vertex x = #(-b)/(2a)# = #(- (-24))/(2 xx 4)# = 3

Take a few points on either side of x = 3

x : y 6 : 1 5 : -19 4 : -31 3 : -35 2 : -31 1 : -19 0 : 1

Plot the points. Join all the points with the help of a smooth curve.

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Answer 2

To graph the quadratic equation ( y = 4x^2 - 24x + 1 ), you can follow these steps:

  1. Find the vertex using the formula ( x = -\frac{b}{2a} ).
  2. Find the y-coordinate of the vertex by substituting the x-value into the equation.
  3. Find the y-intercept by setting ( x = 0 ) and solving for y.
  4. Find the x-intercepts by setting ( y = 0 ) and solving for x using the quadratic formula or factoring.
  5. Plot the vertex, y-intercept, and x-intercepts on the coordinate plane.
  6. Use the symmetry of the parabola to plot additional points on the graph if needed.
  7. Draw a smooth curve passing through the plotted points to complete the graph.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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